本文共 1161 字,大约阅读时间需要 3 分钟。
int InversePairs(int* data, int length){ if(data == NULL || length < 0) return 0; int* copy = new int[length]; for(int i = 0; i < length; ++ i) copy[i] = data[i]; int count = InversePairsCore(data, copy, 0, length - 1); delete[] copy; return count;}int InversePairsCore(int* data, int* copy, int start, int end){ if(start == end) { copy[start] = data[start]; return 0; } int length = (end - start) / 2; int left = InversePairsCore(copy, data, start, start + length); int right = InversePairsCore(copy, data, start + length + 1, end); // i初始化为前半段最后一个数字的下标 int i = start + length; // j初始化为后半段最后一个数字的下标 int j = end; int indexCopy = end; int count = 0; while(i >= start && j >= start + length + 1) { if(data[i] > data[j]) { copy[indexCopy--] = data[i--]; count += j - start - length; } else { copy[indexCopy--] = data[j--]; } } for(; i >= start; --i) copy[indexCopy--] = data[i]; for(; j >= start + length + 1; --j) copy[indexCopy--] = data[j]; return left + right + count;}